-16x^2-50x-5=0

Solution for -16x^2-50x-5=0 equation:

-16x^2-50x-5=0

a = -16; b = -50; c = -5;
Δ = b2-4ac
Δ = -502-4·(-16)·(-5)
Δ = 2180
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2180}=\sqrt{4*545}=\sqrt{4}*\sqrt{545}=2\sqrt{545}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-50)-2\sqrt{545}}{2*-16}=\frac{50-2\sqrt{545}}{-32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-50)+2\sqrt{545}}{2*-16}=\frac{50+2\sqrt{545}}{-32}
$